The floor of the denormalized floating place selection is less complicated because the floor is $0$ or $-one$, depending on the indicator. One thing that may be intriguing relating to this is always that if $n>0$ is big enough, there won't be any representable non-integers. $endgroup$ Kyle Miller H2o just https://goo.gl/maps/J8vDwT71H1misjJa8